2hi g h2 g i2 g

Assuming all gases are at the same Question: The following reaction was performed in a sealed vessel at 721 ∘C∘C : H2(g)+I2(g)⇌2HI(g)H2(g)+I2(g)⇌2HI(g) Initially, only H2H2 and I2I2 were present at concentrations of [H2]=3.200 M, and [HI] = 3.02×10-2 at 907. Question: What is the free energy change, ΔG° (kJ), for the equilibrium between hydrogen iodide, hydrogen, and iodine at 453°C? Kc = 0. 2HI(g)⇌H2(g)+I2(g) Kc=[H2]/[I2][HI]^2. See answers.35 M0. A) 4 Fe (s) + 3 O2 (g) 2 Fe2O3 (s) B) H2 (g) + Cl2 (g) 2 HCl (g) C) 2HI (g) H2 (g) + I2 (g) D) 2 SO3 (g) 2 SO2 (g) + O2 (g) E) N2 (g) + 3 H2 (g) 2 NH3 (g), 43) Of the following equilibria, only _____ will shift to the left in H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at concentrations of [H2]=3. A reaction vessel contains 0. a) Carefully complete the energy diagram by drawing a curve that accurately shows the progress of Question: Consider the following reaction for the decomposition of HI at a certain temperature 2HI(g) --> H2(g) + I2(g) the average rate of disappearance of HI over the period from t = 0 to t = 5. At 500 °C, hydrogen iodide decomposes according to 2 HI (g) — H2 (g) +1_ (8) For HI (g) heated to 500 °C in a 1.80×10-4 mol L-1 s-1 If the experiment has an initial HI concentration of 0.42 mol of H2 were placed in a 1. For the following systems at equilibrium A:B:2NOCl (g)H2 (g)+I2 (g)⇌⇌2NO (g)+Cl2 (g)2HI (g)A:2NOCl (g)⇌2NO (g)+Cl2 (g)B:H2 (g)+I2 (g)⇌2HI (g) classify these changes by their effect.2. B.82 × 10-1. What will be the concentration of HI after t = 4. 2HI (g) → H2 (g) + I2 (g) The rate constant for this reaction is 1.38 x 10-4 mol-1 L s-1 and at 500 oC, the rate constant k has the value 7. Shown below is an incomplete energy diagram for the reaction. Similar questions.59×10 −3 MM , [H2]=[H2]= 4. C. The law of mass action best fits which of the following descriptions? Find the equilibrium expression for the reversible reaction below.60 mol/L, [H2] = .The Soviet defensive effort frustrated Hitler's attack on Moscow, the capital and largest city of the Soviet Union.036. 0. Phát biểu nào sau đây về sự trao đổi năng lượng của phản ứng trên là đúng? A. H2 (g) + I2 (g) yields (k1 on top of the arrow) 2HI (g) (one step reaction)Mechanism b. H2 (g)+I2 (g)↽−−⇀ 2HI (g)𝐾= [HI]2 [H2] [I2]H2 (g)+I2 (g)↽−−⇀ 2HI (g)K= [HI]2 [H2] [I2] For the reaction 2HI (𝑔)↽−−⇀ H2 (𝑔)+I2 (𝑔)2HI (g)↽−−⇀ H2 (g)+I2 (g) select the equilibrium constant Hydrogen iodide can decompose into hydrogen and iodine gases. calculate the concentrations of all species when equilibrium is reached.Ea = - (8.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C, what is the equilibrium concentration of H2 (g)? Question: Consider the second-order reaction: 2HI(g) →H2(g) + I2(g) Use the simulation to find the initial concentration (HI), and the rate constant k for the reaction.9 g I2. Equilibrium concentration stays. Run in the reverse direction to restablish equilibrium.30 kJ/mol at 25°C. Calculate the concentration of HI at equilibrium. The value of Keq for this reaction is _____. So if you add heat, more N2 (g) and H2 (g) will be created and balance out the reaction.50 M? [H2] = 0. 2HI (g)?H2 (g)+I2 (g) This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.87×10 −4 MM , and [I2]=[I2]= 4. At equilibrium, the flask contains 90.65 M HBr and no product.2. Thank you.56×10−3 M , [H2]= 4. 2HI(g) = H2(g) + I2(g) Calculate Kc at this temperature for the following reaction: HI(g) =1/2H2(g) + 1/2I2(g) This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.0500 M . Khi tăng nhiệt độ, cân bằng trên chuyển dịch theo chiều nghịch.761 g H2 and 96. Consider the following exothermic reaction: 2HI (g) ⇆ H2 (g) + I2 (g) A) What will happen to the reaction mixture at equilibrium if an inert gas is added? [1] The equilibrium will shift to the left. Question: Assuming all gases are at the same temperature and pressure, how many milliliters of hydrogen iodide are produced from 150 mL of H2? H2 (g)+I2 (g)→2HI (g) Express your answer with the appropriate units. Consider the reaction H2(g) + I2(g) <--> 2HI(g).00 mole of H2, 1. 2H18) <--> H2(g) + 12(g) + heat Shift (Left, Right, or no shift) Change Reason Hydrogen is added lodine is removed Some argon is added Volume of container is doubled Volume of container is doubled Temperature is decreased The reaction vessel is heated Edit View Insert Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0and the rate constant k for the reaction.0 g of HI (g) is injected into a 4. loading. Drag the appropriate items to their respective bins. The equilibrium constant, Kc, for the following reaction is 1.300 mol of I2 were placed in a 1.4 x 10^-9 l/(mol x s) at In an experiment, 0. The rate constant at 555 K is 3." Russian media reported that two unmanned The Battle of Moscow was a military campaign that consisted of two periods of strategically significant fighting on a 600 km (370 mi) sector of the Eastern Front during World War II, between September 1941 and January 1942. Given the partial pressures of HI, H2 and I2 at equilibrium (PHI = 0.85 mol/L, [I2] = .1×10−4 (b) H2 (𝑔)+I2 (𝑔) 2HI (𝑔) T=400°C 𝐾𝑝=50. K = [HD]2 [H2][D2] (15.7.95M. Question: What is the free energy change, ΔG°, for the equilibrium between hydrogen iodide, hydrogen, and iodine at 311°C? Kc = 0. In a certain experiment the decomposition of hydrogen iodide on finely divided gold is zeroth order with respect to HI. a. Who are the experts? Experts have been vetted by Chegg as specialists in this subject. See Answer Question: For the reaction: 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0.390 mol/L, what is the concentration of HI after 28. Step 1. Please show work. Suggest Corrections.27 mol/L.06 M The equilibrium constant, K c, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C.50 M? [H2] = 0.00 mol of HI (g) is introduced into the reaction vessel In which direction will the position of the equilibrium be shifted for each of the following changes? Explain your answers.B . The equilibrium concentration of I2I2 is 0. Part A.0. Consider the following reaction: H2 (g) + I2 (g) ⇌ 2 HI (g) Complete the following table.100 atm. Step 1. Thus, increasing the temperature has the effect of increasing the amount of one of the products of this reaction. Calculate the magnitude of Kc for the reaction.00160 M-1 .0200 M . At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇌ 1/2 H2 (g) + 1/2 I2 (g) The value of Keq for the equilibrium H2 (g) + I2 (g) 2HI (g) is 794 at 25 °C. Express your answer using two significant figures.0156 at 400ºC.txet egami debircsnart wohS .0890 M HI, 0. Chemistry questions and answers. 2HI (g) = H2 (g) + I2 (g) Calculate Kc at this temperature for the following reaction: HI (g) =1/2H2 (g) + 1/2I2 (g) 6) a CO2 g+H2 g⇌CO g+H2O g.00 L reaction vessel that contains 20.038 M H2, and 0. Balance the The oxidation state of an element in its elementary state, such as H₂ or I₂, is always 0. The reaction described by H2 (g) + I2 (g) yields 2HI (g) has an experimentally determined rate law of rate of reaction= k [H2] [I2]some proposed mechanisms for this reaction are: Mechanism a. ÐÏ à¡± á> þÿ h j Exercise 14. There are 2 steps to solve this one.5, What were the equilibrium concentration for H2, I2 and HI? N2 (g) + 3 H2 (g) ↔ 2 NH3 (g) ΔH = −92kJ/mol.6 × 10−3 2 H I ( g ) → H 2 ( g ) + I 2 ( g ) ; At 25 C If 1. B. A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine:2HI (g) ↔ H2(g) + I2(g)When the system comes to equilibrium at 425 °C, PHI = 0.80×10-2 at 698 K. at a particular temperature, K= 1. Chemistry.87×10 −4 MM .00 L vessel at 698 K. Thus, increasing … H2 (g) + I2 (g) → 2HI (g) A student makes the following statements: Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in … H2(g) and I2(g) can react to produce HI(g), as represented above. 2HI(g) H2(g) I2(g) K for the reaction is 0.9 g I2.00414 mol of I2, and 0.65 x 10-2 mol-1 L s-1.00-L flask containing an equilibrium mixture of the three gases, there are 0.200 atm, and a partial pressure of HI of 0.2 kcal/mol (−9. 21. Consider the following chemical reaction: CO (g) + 2H2 (g) ⇋CH3OH (g) At equilibrium in a particular experiment, the concentrations of CO Question: Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. Assume that all concentrations are equilibrium concentrations in M .8. Calculate K for this reaction.2 at 448∘C (c) Na2SO4 ⋅ 10H2O (s) ⇌ Na2SO4( s)+ 10H2O (g) KP = 4. Qc=[HI][H2][I2] There are 2 steps to solve this one. Will the equilibrium concentration of HI increase, decrease, or remain See Answer. The equilibrium constant, Kc, for the following reaction is 1. Express your answer using two significant The decomposition of HI (g) is represented by the equation 2HI (g) = H2 (g) + I2 (g) The following experiment was devised to determine the equilibrium constant of the reaction. H2 (g)+I2 (g)⇌2HI (g) has Δ H =−2. Choose the one alternative that best completes the statement or answers the question.0013 verified answered • expert verified H 2 (g)+I 2 (g)→2 H I (g) ΔH∘r x n=−9.00 L vessel where the following equilibrium was established: H2 + I2 <-----> 2HI For this reaction, Kc = 49.016 Initially a container contains 0. This problem has been solved! \[\ce{H2(g) + I2(g) \rightleftharpoons 2HI(g)} + \text{heat} \label{15.0175 mol/L. (a) Assuming ideal gas behavior, calculate the mass of H 2 present in the reaction mixture at equilibrium.15) K p = K ( R T) Δ n.27 mol/L I have the answer but need to see the work.0 minutes? 1 pts.`040`. The equilibrium reaction can be written as follows: 2HI(g) ⇌ H2(g) + I2(g). For the reaction H2(g)+I2(g)⇌2HI(g), Kc = 55., When the substances in the equation below are at equilibrium, at pressure P and temperature T, the equilibrium can be shifted to favor the The correct answer is 0. Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.00623 mol of H2, 0.0 (at 400ºC) If the reaction vessel initially contains 0. Suppose 0.0 = ]2I[ ,M 001. We reviewed their content and use your Final answer.75M[H2]=3.) Convert the values of Kc to values of K p or the values of K p to values of Kc.25 Consider the reaction: H2 (g) +I2 (g) 2 HI (g) A reaction mixture in a 3.00-L container.15 M I2 at equilibrium.75 M I2, what is the equilibrium concentration of HI? The activation energy for the decomposition of Hi(g) to H2(g) and I2(g) is 186 kJ/mol.09 M .00 L reaction vessel at 400ºC.016 Initially a container contains 0. Chemistry Chemical Equilibrium Equilibrium Constants. Express your answer in moles per liters to three significant figures. Thanks! HI decomposes to H2 and I2 by the following equation: 2HI (g) → H2 (g) + I2 (g);Kc = 1.5 k J/m o l r x n H 2 (g) and I 2 (g) can react to produce HI (g) , as represented above.714 mole of H2, 0.70 M0. Chemistry. The temperature is expressed as the absolute temperature in Kelvin. Use data from Appendix C to calculate the equilibrium constant, K, and Δ G ∘ at 298 K for each of the following reactions. Ở nhiệt độ không đổi, khi tăng áp suất thì cân bằng không bị chuyển dịch.45 M HI and no product. 2HI(g) H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and products when 0.450 mol/L∙s. The reaction.122 at For the reaction 2HBr(g) ⇌ H2(g) + Br2(g) K = 2. These results can be used to calculate the standard Gibbs free … verified answered • expert verified H 2 (g)+I 2 (g)→2 H I (g) ΔH∘r x n=−9. Question: Gaseous hydrogen iodide is placed in a closed container at 425∘C, where it partially decomposes to hydrogen and iodine: 2HI(g)⇌H2(g)+I2(g) At equilibrium it is found that [HI]= 3. 0. The answer is .00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H. About Quizlet; How Quizlet works; Careers; Advertise with us; Get the app; For students.0156 at 400ºC.484 M , [I2]=0. The equilibrium concentration of I2 is 0. Solution. [HI] = M [H2] = M [I2] = M. H2(g) + I2(g) 2HI(g) When equilibrium is achieved the concentration of HI is 0. What is the equilibrium concentration of H2? 2)For the reaction: 2HBr (g) ↔ H2 (g) + Br2 (g) Initially a container contains 0. 1 Answer Stefan V. Tổng nhiệt phá vỡ liên kết của chất phản ứng lớn hơn nhiệt tỏa ra khi tạo thành Question: Hydrogen iodide decomposes according to the equation 2HI(g) H2(g) + I2(g), for which Kc = 0.4 kg of CO 2 at 825 K.20 M of H₂ and 1. What will be the concentration of HI after t = 9. Find [H2] at 340 ∘C . What is the equilibrium constant for the reaction H2 (g)+I2 (g)⇌2HI (g) at 700 K? This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.00-L reaction The equilibrium constant for the gas phase reaction H2 (g) + I2 (g) 2HI (g) is Keq = 50 at 25 °C.0 minutes? 1 pts. CH 4 (g) + CO 2 (g) ⇌ 2CO(g) + 2H 2 (g); K p = 450.0960 atm. Express your answer using two significant The decomposition of HI (g) is represented by the equation 2HI (g) = H2 (g) + I2 (g) The following experiment was devised to determine the equilibrium constant of the reaction. What is the reaction quotient, Q, for this system when [H2] = 0. Answer: Increasing the temperature will cause the equilibrium to shift towards the reactants (left). Part A Calculate the equilibrium constant (Kc) for the reaction at this temperature.00 × 10^−19 at 298 K what can be said about this reaction at this temperature? The equilibrium lies far to the left. H2(g) + I2(g) → 2HI (g) ∆H = +11,3 kJ.70 atm 13. 1)For the reaction in the previous problem, that is, 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0. Calculate K for 2HI (g)⇌H2 ( g)+I2 ( g) at this temperature. The law of mass action best fits which of the following descriptions? Find the equilibrium expression for the reversible reaction below. At this temperature, what is the value of Keq for … The equilibrium concentration of I2 is 0.290 at 400 K.0 (c) CO2 (𝑔)+H2 (𝑔) CO (𝑔)+H2O (𝑔) T=980°C 𝐾𝑝=1.10x10^-5 L/mol*s / 9.00-L reaction vessel at 400ºC. (Express your answer to four significant figures and include the appropriate units.90×1010 s ( [HI]t) for a reaction starting under the condition in the simulation? Chemistry questions and answers. For the reaction 2HI(g) H2(g) +I2(g), the degree of dissociation (a) of HI(g) is related to equilibrium constant kp by the relation? Open in App. Calculate the concentration of HI at equilibrium. Who are the experts? Experts have been vetted by Chegg as specialists in this subject. Answer to Solved Calculate Kc for the reaction 2HI(g) = H2(g) + I2(g) Science; Chemistry; Chemistry questions and answers; Calculate Kc for the reaction 2HI(g) = H2(g) + I2(g) given that the concentration of each species at equilibrium are as follows: [HI] = 0.The amount of I2 produced over time is measured by opening each 2HI(g)⇌H2(g)+I2(g)2HI(g)⇌H2(g)+I2(g) At equilibrium it is found that [HI]=[HI]= 3. The equilibrium constant, Kp, is related to the standard Gibbs free energy change, ΔG°, through the equation: Find Kc for the reaction. Step 2. B) The equilibrium will shift to th; The following reaction is exothermic. At equilibrium, the flask contains 90.43 atm b! 3.484 M , [I2]=0. Show transcribed image text. ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0. HI (g) is introduced into five identical 400-cm3 glass bulbs, and the five bulbs are maintained at 623 K. The following reaction was performed in a sealed vessel at 723 ∘C : H2 (g)+I2 (g)⇌2HI (g) Initially, only H2 and I2 were present at concentrations of [H2]=3. 0.0 x 10-4 M? Question: Calculate ΔG° for each of the following reactions from the equilibrium constant at the temperature given. Expert Answer.6} \] Increasing the temperature of the reaction increases the internal energy of the system. H2(g) +D2(g) ⇌ 2HD(g) (15.50-L container initially holds 0.15) (15.

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0×10−3M and the initial concentrations of H2, and the initial concentrations of H2, and I2 are both 1. H2 (g)+I2 (g) = 2HI (g) At this temperature, 0. Thus an equilibrium mixture of H2, D2, and HD contains significant concentrations of both product and reactants.32 g I2.26 atm pressure of HI is admitted to the container, and it is allowed to come to equilibrium again.2.30 kJ/mol at 25°C. In another study of the formation of HI(g), H2(g) and I2(g) were placed in a sealed container at a certain temperature.4x10^-9 L/mol.15M, 0. If an additional 1. You'll get a detailed solution from a subject matter expert that helps you learn core concepts.95×10-2 at 731 K.6} \] Increasing the temperature of the reaction increases the internal energy of the system.6x10^-1 atm.s at 500 K Express your answer in moles per liters to On one set of axes, sketch concentration vs time curves for H2 and HI.40-L reaction chamber.80×10-4 mol L-1 s-1 If the experiment has an initial HI concentration of 0.550 M b. What is the value of Keq for the equilibrium below? 1/2H₂ (g) + 1/2 I₂ (g) ⇌ HI (g), The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2 HI (g) is 794 at 25°C. at 825 K.15 K are summarized in Table 4.1 x 10-2 M, how many minutes will it take for the concentration to. Question: At 500 °C, hydrogen iodide decomposes according to 2HI(g)↽−−⇀H2(g)+I2(g) For HI(g) heated to 500 °C in a 1. About us.414 M, L) = 0. 0.4 H2(g) 0 I―I 151 I2(g) 61. Show below how to derive the Keq . Chemistry questions and answers.550 mol HI was injected into a 2.59×10 −3 MM , [H2]=[H2]= 4. Equilibrium concentration of H1 increases 2. Kp = K(RT)Δn (15.016 Initially a container contains 0. Find step-by-step Chemistry solutions and your answer to the following textbook question: Hydrogen iodide decomposes according to the reaction $2 \mathrm { Hl } ( \mathrm { g } ) \rightleftharpoons \mathrm { H } 2 ( \mathrm { g } ) + 12 ( \mathrm { g } )$ A sealed 1.2Group of answer choices0. Flashcards; Test; Learn Study with Quizlet and memorize flashcards containing terms like The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2HI (g) is 794 at 25 °C. Study with Quizlet and memorize flashcards containing terms like 42) Of the following equilibria, only _____ will shift to the left in response to a decrease in volume. where K K is the equilibrium constant expressed in units of concentration and Δn Δ n is the difference between the numbers of moles of gaseous products and gaseous reactants ( np −nr n p − n r ). If the initial concentration of HI in a container is 5. What is the free energy change, ΔG°, for the Question.2HI (g) -> H2 (g) + I2 (g) There are 2 Hydrogen atoms and 2 Iodine atoms on the right so the have to be 2 of each on the left as well, so there are 2 HI molecules on the left. 2HI (g) H2 (g) + I2 (g) Calculate the equilibrium concentrations of reactant and products when 0. What is the new partial pressure of HI? H2(g) + I2(g) → 2HI(g) (a) Using the equation ΔH o rxn = ∑(BE(reactants)) − ∑(BE(products)) kJ/mol (b) Using the equation ΔH o rxn = ∑(nΔH o f (products)) − ∑(mΔH o f (reactants)) kJ/mol Bond BE kJ/mol Substance ΔH o f kJ/mol H―H 436. (b) What is the percent yield of the reaction under these conditions? (not answered) Consider the following exothermic reaction below.28×10 10 s ([HI]t) for a reaction starting under the condition in the simulation?. 1)For the reaction in the previous problem, that is, 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0.6 g HI.80M. Chemistry questions and answers.51 x 10^-9 L/mols at 500 K and 1. The rate constant for the decomposition of hydrogen iodide (HI) at 700oC equals 0.314 J/molK) (ln 1. At this temperature, what is the value of Keq for the equilibrium You'll get a detailed solution from a subject matter expert that helps you learn core concepts.220 M e. What will be the concentration of HI after t = 9. Science. Calculate the concentration of H2 at equilibrium.43×10-2 at 1110 K.20M.550 mol HI is injected into a 2. For the reaction 2HI (g) ⇌H2 (g)+I2 (g), Kc= 0. Transcribed image text: 25.15) K p = K ( R T) Δ n.708 atm, and PH2=P12=0. At this temperature, what is the value. Solution. The equilibrium constant, Kc, for the following reaction is 1. The rate constant at 555 K is 3. 2HI (g) H2 (g) + I2 (g) Calculate the equilibrium concentrations of reactant and products when 0. Qc=[HI][H2][I2] There are 2 steps to solve this one.9 and 4 over a wide temperature range (100-1000 K).0300 M .75-L flask at a certain temperature initially contains 0.072 M at 430 degree C. HI decomposes to H2 and I2 by the following equation: 2HI (g) → H2 (g) + I2 (g);Kc = 1.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25 ∘C , what is the equilibrium concentration of H2 (g)? a 0 H2 (g)+I2 (g)→2HI (g) ΔH∘rxn=−9. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. The reaction described by H2 (g) + I2 (g) yields 2HI (g) has an experimentally determined rate law of rate of reaction= k [H2] [I2]some proposed mechanisms for this reaction are: Mechanism a.50×10-3M at 400 K, which one of the following statements is H2(g) + I2(g) ⇌ 2HI(g) and more. 2HI(g)?H2(g)+I2(g) Determine the reaction quotient expression for the reversible reaction below. The equilibrium constant Kc for the reaction H2 (g) + I2 (g) <=> 2 HI (g) is 54.50 M? 613.9) The equilibrium constant expression for this reaction is.60 M HI, 0.3 kg of CH 4 and 55. Phản ứng giải phóng nhiệt lượng 11,3 kJ khi 2 mol HI được tạo thành. Copy link. For the reaction H2(g) + I2(g) ⇌ 2HI(g) K= 57. Question: At 500 °C, hydrogen iodide decomposes according to 2HI(g)↽−−⇀H2(g)+I2(g) For HI(g) heated to 500 °C in a 1.250 M 0.353 moles of HI are introduced into a 1.015 2HI (g) [image] H2 (g) + I2 (g) 6 kJ 9 kJ 15 kJ 20 kJ 22 kJ. Explain the concept of a dynamic equilibrium.)The equilibrium constant, Kc, for the following reaction is 1. Chemistry. 0. ÐÏ à¡± á> þÿ h j Exercise 14.0049. 2HI (g) leftright arrow H2 (g) + I2 (g) What will happen to the reaction mixture at equilibrium if some H2 (g) is removed? A) The equilibrium will shift to the left. H2(g) + I2(g) ⇌ 2HI (g) = -9,6 kJ.100 M, [I2] = 0.393 M. Question: Consider the equilibrium system involving the decomposition of hydrogen iodide.85 mol/L, [I2] = 0.0244 Question: In an experiment hydrogen iodide was found to be 24.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0. What is the mass of HI in the flask? Senior News Reporter.00 L reaction vessel at 400ºC.2. To form HI The equilibrium constant, Kc, for the following reaction is 1. View the full answer. H2 (g) + I2 (g) yields (k1 on top of the arrow) 2HI (g) (one step reaction)Mechanism b. Since there is an equal number of each element in the reactants and products of H2 + I2 = 2HI, the equation is balanced.4x10^-2 atm, pI2=4.275 M The value of Keq for the equilibrium. Flashcards; Test; Learn Study with Quizlet and memorize flashcards containing terms like The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2HI (g) is 794 at 25 °C. If the initial concentration of HI in a container is 3.638 0. Equilibrium concentration of H1 decreases 3. only products are Question: Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. Chemistry questions and answers.53 M0.5kJ/molrxn. About Quizlet; How Quizlet works; Careers; Advertise with us; Get the app; For students.484 M , and [HI]=4. Calculate the concentrations of the gases at equilibrium.8×10−2 at 700 K. Nhận xét nào sau đây không đúng? A. A reaction vessel contains 0. s. 2HI(g)⇌H2(g)+I2(g) Kc=[H2]/[I2][HI]^2. What will be the concentration of HI after t = 4. What is the equilibrium constant, KcKcK_c, for the The decomposition of HI is described by the following equations: 2HI(g) -----> H2(g) + I2(g) R = k [HI]2 At 400 oC, the rate constant k has the value 8. Of 0. The equilibrium constant for a system will be symbolized by the letter: K. A flask originally contains 0.040. The equilibrium constant (Kc) for the reaction H2 (g) + I2 (g) <=> 2HI (g) is 54.5x10^-3 atm and pHI=2. products predominate b. H2 (g) + I2 (g) yields (k1 on top of the arrow) 2HI (g) (one step reaction)Mechanism b.50 M.94×10-2 at 728 K. Balance the This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. 0. This is because the reaction is exothermic and releases heat. Who are the experts? Experts have been vetted by Chegg as specialists in this subject.0 atm.65 M HBr and no product. So, this is indeed a redox reaction because oxidation (the loss of electrons as seen in The equilibrium constant, Kc, for the following reaction is 1.00 L container to react. Chemistry questions and answers.2 at 430 degree C. + 2 H2(g) ⇌ CH3OH (g)In an experiment, 0. 0.0890 M HI, 0.072 M, what was the initial concentration of HI? H2 (g) + I2 (g) ⇌ 2HI (g) Kc=54.0960 atm.300 mol of H2 and 0.87×10 −4 MM .25 Consider the reaction: H2 (g) +I2 (g) 2 HI (g) A reaction mixture in a 3.50 s is found to be 0.0156 at 400ºC. The potential energy of the reactants is indicated on the diagram. ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0.0049. Q. Determine the initial and equilibrium concentrations of HI if the initial concentrations of H2 and I2 are both 0.6 × 10−3 at 25∘C If 1.85 mol/L, [I2] = .020 H2 (g) + I2 (g) → 2HI (g) What is the free energy change, Δ G ° (kJ), for the equilibrium between Chemistry question on rate laws. where K K is the equilibrium constant expressed in units of concentration and Δn Δ n is the difference … \[\ce{H2(g) + I2(g) \rightleftharpoons 2HI(g)} + \text{heat} \label{15. Which statement is correct about this reaction mixture? Expert Answer.The amount of I2 produced over time is measured by opening each 2HI(g)⇌H2(g)+I2(g)2HI(g)⇌H2(g)+I2(g) At equilibrium it is found that [HI]=[HI]= 3.643 moles of I2 are at equilibrium in a 17. The equilibrium concentration of I2 is 0. What is the equilibrium constant, Kc, for the reaction at this temperature? H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at concentrations of [H2]=3. What is the rate of appearance of I2 over the same period? a.51x10^-9 L/mols) ( (1/ The value of Keq for the equilibrium H2 (g) + I2 (g) ⇌ 2HI (g) is 794 at 25 °C.B. Chemistry. B. 0. H2 (g) and I2 (g) can react to produce HI (g), as represented above.0 H―I 298.] = 0.200 M, and [HI] = 3.68×1010 s ([HI]t for a reaction starting under the condition in the simulation? k = 6. What is the activation energy of this reaction? Question: Given a reversible chemical reaction: H2(g) + I2(g) ⇌ 2HI(g) Kc = 64.) b) Calculate the equilibrium constant, K. Chemistry questions and answers.55M. Part A. The potential energy of the reactants is indicated on the diagram.0 fo 2H fo erusserp laitrap a htiw erutarepmet dexif a ta muirbiliuqe ta si )g(IH2 ⇌ )g(2I + )g(2H metsys ehT . Chemistry questions and answers.51 x 10^-9 L/mols at 500 K and 1. please do step by step. Study with Quizlet and memorize flashcards containing terms like If a given process proceeds spontaneously toward the products, the value of the reaction quotient Q is _ the equilibrium constant K, and ΔG for the reaction will be _. Chemistry questions and answers. Shown below is an incomplete energy diagram for the reaction. Part A. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Part A Calculate the equilibrium constant (Kc) for the reaction at this temperature.64 moles of HI (g), 0. (a) N2 (𝑔)+O2 (𝑔) 2NO (𝑔) T=2000°C 𝐾𝑝=4.Ea = - (8.250 M 0 We know the reaction proceeds from left to right because there is no HI present initially and the equilibrium amount of HI is 0.761 g H2 and 96.10 x 10^-5 L/mols at 600 K. H2(g) + I2(g) 2HI(g) Initial 0. Russia said it had suppressed a drone attack on Moscow carried out by Ukraine which it has accused of "international terrorism. Consider the equilibrium reaction and its equilibrium constant expression.60 mol/L, [H2] = . 2HI(g)?H2(g)+I2(g) Here’s the best way to solve it.0249 0. Mar 4, 2018 #K_c = 2.0156 at 400°C 單選: 2.10 x 10^-5 L/mols at 600 K.428 moles of H2, and 0.0411 0. If the initial concentration of HI is 4.21 If at equilibrium the reaction vessel contains 1.038 but I need detailed steps how to get there.75 M H2 and 0.42 times 10^{-7} L/mol . How does the magnitude of Kp for the reaction 2HI(g)⇋H2(g)+I2(g) change if the equilibrium is written 6HI(g)⇋3H2(g)+3I2(g)? It is cubed. Ở nhiệt độ không đổi, khi tăng nồng độ H2 hoặc I2 thì You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Consider the reaction H2(g) + I2(g) <--> 2HI(g). roughly equal amounts of products and reactants are present d. If an additional 1.80×10-2 at 698 K.0% reacted at 731 K.2I M 894.100 M, [I2] = 0. (Please show me the step-by-step math needed to achieve this 2 H I (g) ⇌ H 2 (g) + I 2 (g), For the above reaction the degree of dissociation ( α ) of HI (g) is related to equilibrium constant K p by the expression : View Solution The concentrations of HI and I2 will increase as the system is approaching.Q.148 atm of HI(g) is sealed in a flask, what is the pressure of each gas when equilibrium is established What is the standard free energy change, ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0.53×1010 s ([HI]t) for a reaction starting under the condition in the simulation? Given from simulation: Rate Law: k[HI]^2 Question.059 g H2 and 4. 1.55M respectively.5 k J/m o l r x n H 2 (g) and I 2 (g) can react to produce HI (g) , as represented above.

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Unlock. At equilibrium, pH2= 1.c etanimoderp stnatcaer . An 85.Moscow was one of the primary military and political It was the latest step in an ongoing crackdown on L. Who are the experts? Experts are tested by Chegg as specialists in their subject area. 2HI(g) > H2(g) + I2(g) Calculate Kc at this temperature for: H2(g) + I2(g) 2HI(g) Kc= 2. Which statement is correct about this reaction mixture? View Available Hint(s) The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54. Chemistry questions and answers. Question: The standard free energy of formation of gaseous hydrogen iodide is1. In a certain experiment the decomposition of hydrogen iodide on finely divided gold is zeroth order with respect to HI.80×10-2 at 698 2HI(g) --> H2(g) + I2(g) Rate = -d[HI]/dt = k = 1. The equilibrium constant, Kc, for the following reaction is 1. The equilibrium constant, K c, for the reaction H 2 ( g) + I 2 ( g) ⇄ 2HI ( g) at 425°C is 54.09 M . When the system comes to equilibrium at 400°C, what will be the total pressure inside the reaction vessel? 2HI (g) % H2 (g) + 12 (g), Kc = 0.42 mol of CO and 0. For the reaction in the previous problem, that is, 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0.. Chemistry questions and answers. 2HI (g) H2 (g) + I2 (g) K = [H2] [I2] = 2.00 mole of I2, and 1. Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. Expert-verified. CO2 g+H2 g⇌CO g+H2O g. In a 2.`3 at 430 degree C`. (a) N2( g)+ 3H2( g)⇌ 2NH3( g) Kc = 0. H2 (g) + I2 (g) ⇋2HI (g) is 794 at 25 °C.3 at 700 K.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.4 x 10-2 M, how many minutes will it take for the concentration to be reduced to 8.16 M and their equilibrium concentrations are both 0. What is the standard free energy change, ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0. Consider the reaction: 2 HI (g) ⇌ H₂ (g) + I₂ (g) Kc = 7. View Available Hint (s)for Part A Reset Help System A Increase HI decomposes to H2 and I2 by the following equation: 2HI(g) → H2(g) + I2(g);Kc = 1.15) (15. 0. freedom in Russia, including a law passed in December against depictions of gay lifestyles — what the government called "gay Investigators examine an area next to a damaged building in the "Moscow City" business district after a reported drone attack in Moscow, Russia, early Tuesday, Aug. Question: The decomposition of hydrogen iodide, 2HI (g) ----> 2H2 (g) + I2 (g), has rate constants of 9. Find Kp for the reaction 2HI (g) H2 (g)+ I2 (s) at this temperature. Calculate Kc for the reaction 2HI(g) = H2(g) + I2(g) given that the concentration of each species at equilibrium are as follows: [HI] = 0. Chemistry questions and answers. Iodine is in Group VIIA, so it has an oxidation number of -1 in both the reactant I2 and product HI.76×1010 s ([HI]t) for a reaction starting under the condition in the simulation? Express your answer in moles per liters to three significant figures. [4] The reaction will stop.39 M HI and no product. The equilibrium constant, Kc, for the following reaction is 1.16 M and their equilibrium concentrations are both 0.200 M, and [HI] = 3. Step 4: Substitute Coefficients and Verify Result. What is the equilibrium concentration of H2? Question: Hydrogen iodide decomposes according to the equation 2HI (g) H2 (g) + I2 (g), for which Kc = 0.10) with K varying between 1. Run in the forward direction to restablish equilibrium. Study with Quizlet and memorize flashcards containing terms like Calculate Kc for the reaction 2HI(g) ⇌ H2(g) + I2(g) given that the concentrations of each species at equilibrium are as follows:[HI] = 0..0275 M c. Chemistry Chemistry questions and answers Determine the reaction quotient expression for the reversible reaction below. The reaction is second order and has a rate constant equal to 1.G. 25.13 M1.033M, and 0. Consider the following system at equilibrium at 698 K: 2HI (g) H2 (g) + I2 (g) When some HI (g) is added to the equilibrium system at constant temperature: The reaction must: fill in the blank 1 A.550 mol HI was injected into a 2. Find Ea.708 atm, and PH2 = PI2 = 0. 1.07x1010 s ( [HI]+) for a reaction starting under the condition in the simulation? Express your answer in moles per liters to three significant figures.200 mol H2 and 0. About us. Therefore, in the reaction H₂(g) + I₂(g) → 2HI(g), both hydrogen and iodine change their oxidation states: Hydrogen from 0 to +1 and Iodine from 0 to -1.6 x 10-3 L mol-1 s-1 at 700 °C. (Express your answer using two H2 (g) +I2 (g) <-----> 2HI (g) At equilibrium in a particular experiment, the concentrations of H2,I2 , and HI were 0. If 1.80×10-2 at 698 K.00 mol of HI(g) is introduced into the reaction vessel, what are 2HI(g)⇌H2(g)+I2(g) Select the correct answer below: Qc=[HI]2[H2][I2] Qc=[H2][I2][HI] Qc=[H2][I2][HI]2.53×1010 s ([HI]t) for a reaction starting under the condition in the simulation? Given from simulation: Rate Law: k[HI]^2 k= 6.035 C) 28 D) 397 E) 0.295.414 M, and [HI] = 3. What is the concentration of HI at equilibrium? Group of answer choices a. Hydrogen iodide decomposes according to the equation 2HI(g) H2(g) + I2(g), for which Kc = 0. … Kp = K(RT)Δn (15.10x10^-5 L/mols / 9.5 L container at 758 K, the value of the equilibrium constant, Kc, is.2. The decomposition of hydrogen iodide follows the equation 2HI ( g) → H2 ( g) + I2 ( g).0 = ]2H[ ,L/lom 06.`016 Initially a container contains 0`. [2] The equilibrium will shift to the right. Bin options: 1.550 mol HI was injected into a 2.984 mole of I2, and 0.00 x 102 for the reaction H2 (g) + I2 (g) <-> 2HI (g) In an experiment, 1. The potential energy of the reactants is indicated on the diagram. Shown below is an incomplete energy diagram … For the reaction 2HI(g) H2(g) +I2(g), the degree of dissociation (a) of HI(g) is related to equilibrium constant kp by the relation? Open in App. The standard free energy of formation of gaseous hydrogen iodide is1.484 M , and [HI]=4.51x10^-9 L/mols) ( (1/ The value of Keq for the equilibrium H2 (g) + I2 (g) ⇌ 2HI (g) is 794 at 25 °C. 1, 2023.50 M? 613.25 * 10^(3)# Explanation: You Step 4: Substitute Coefficients and Verify Result. If an additional 1. [HI] = M [H2] = M [I2] = M.75M and [I2]=2. Kc = 56. What is the equilibrium constant for the reaction H2(g)+I2(g)⇌2HI(g) at 700 K? Express your answer using two significant figures.00 L vessel at 698 K. 0.27 mol/L I have the answer but need to see the work.00 L reaction vessel at 400ºC. Unlock., As the reaction quotient Q increases, what is the effect on the Chemistry questions and answers.0 g of l2 (g).2 kJ/mol). What will be the concentration of HI after t = 9. See Answer Balanced Chemical Equation 2 HI → H 2 + I 2 ⬇ Scroll down to see reaction info and a step-by-step answer, or balance another equation.T. C.60 kJ/mol.353 moles of HI are introduced into a 1. Drag the appropriate items to their respective bins. Reaction Information Word Equation … H2 + I2 = HI is a Synthesis reaction where one mole of Dihydrogen [H 2] and one mole of Diiodine [I 2] combine to form two moles of Hydrogen Iodide [HI] Show Chemical … Finally, the standard molar Gibbs Free Energies at 298. Chemistry questions and answers.6 × 10−3 at 25∘C.15 298.215 M H 2, and 0. What is the value of KcKc at this temperature? Express the equilibrium constant to three significant digits. Shown below is an incomplete energy diagram for the reaction. Question: 6) a.75-L flask at a certain temperature initially contains 0. What will be the concentration of HI after t = 4.336 M hydrogen iodide.390 mol/L, what is the concentration of HI after 28.08 ×10 −25 at 25∘C (d) H2O(I) ⇌ H2O(g) KP = 0.00 mole of HI are introduced into a 1. What will be the concentration of HI after t = 1. You'll get a detailed solution from a subject matter expert that helps you learn core concepts.80×10-2 at 698 2HI(g) --> H2(g) + I2(g) Rate = -d[HI]/dt = k = 1. Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. Chemistry. What is the value of Keq for the equilibrium below? 1/2H₂ (g) + 1/2 I₂ (g) ⇌ HI (g), The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2 HI (g) is 794 at 25°C. Expert-verified.70 M I₂, the what is the equilibrium concentration of HI? MULTIPLE CHOICE. 1. What is the value of Keq for the equilibrium below? 1/2 H2 (g) + 1/2 I2 (g) HI (g) A) 1588 B) 0.00 L vessel at 698 K. 0. The equilibrium constant, Kc, for the following reaction is 1. Chemistry Chemistry questions and answers For the reaction 2HI (g)⇌H2 (g)+I2 (g), the equilibrium constant Kc=1. If the initial concentrations of H2 and I2 are both 0.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C, what is the equilibrium concentration of H2 (g)? The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54. 2) Suppose a reaction is started with 0.0 at 700 K what can be said about this reaction at this temperature? A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine: (2pt) 2HI(g) H2( g)+I2( g) When the system comes to equilibrium at 425∘C,PHi=0. With time, the concentrations of H2 and I2 decline, and the concentration of HI increases.s-1 : 2HI (g) → H2 (g) + I2 (g) 1) Based on the units of the rate constant, is the reaction first order or second order? Explain. At this temperature, what is the value. What is the equilibrium concentration of H2? 2)For the reaction: 2HBr (g) ↔ H2 (g) + Br2 (g) Initially a container contains 0. Chemistry questions and answers. What concentration of HI is present at equilibrium? 2HI (g) -> H2 (g) + I2 (g) There are 2 Hydrogen atoms and 2 Iodine atoms on the right so the have to be 2 of each on the left as well, so there are 2 HI molecules on the left. At equilibrium, _____.0 L reaction container initially contains 22.886 mole of HI in a 2.15M and [I2]=2. H2(g)+I2(g)=2HI, Finding out final concentration of H2, I2 an… Balanced Chemical Equation 2 HI → H 2 + I 2 ⬇ Scroll down to see reaction info and a step-by-step answer, or balance another equation. Consider the equilibrium system involving the decomposition of hydrogen iodide.10M and [I2]=2.00 mol of HI(g) is introduced into the reaction vessel, what are 2HI(g)⇌H2(g)+I2(g) Select the correct answer below: Qc=[HI]2[H2][I2] Qc=[H2][I2][HI] Qc=[H2][I2][HI]2.83×10−4 M .016. What is the rate constant at 645 K? The activation energy for the decomposition of HI(g) to H_2(g) and I_2(g) is 186 kj/mol.10M and [I2]=2.0535 0. The reaction rate is a direct function of the reactants concentrations, aA+ bB → cC #"Rate" = k[A]^x [B]^y# Where #a, b, c#: are the stoichiometric coefficients #x, y#: are the reactant orders The … Question: Determine the reaction quotient expression for the reversible reaction below.040; This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.78 atm O 0.815 atm 2.498 M I 2.100 M, [I2] = 0.200 M, and [HI] = 3. View the full answer. The reaction described by H2 (g) + I2 (g) yields 2HI (g) has an experimentally determined rate law of rate of reaction= k [H2] [I2]some proposed mechanisms for this reaction are: Mechanism a.8.87×10 −4 MM , and [I2]=[I2]= 4. 2SO3(g) > 2SO2(g) + O2(g) Calculate Kc at this temperature for the following reaction: SO3(g H2, I2, and HI are introduced into a flask. Calculate the equilibrium concentrations of the three gases. Copy link.323 moles of HI are introduced into a 1. Hydrogen iodide decomposes according to the equation 2HI (g) H2(g) + I2(g), Question: Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. What is the value of Kc at this temperature? Chemistry questions and answers.393 M.0156 at 400ºC.2.040; This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.6 x 10-3 L mol-1s-1 at 700 ºC.83×10−4 M , and [I2]= 4. See Answer Chemistry Chemistry questions and answers Hydrogen iodide decomposes according to the equation 2HI (g) H2 (g) + I2 (g), for which Kc = 0.708 atm, PH2 = PI2), we can substitute them into the equilibrium expression for the reaction, which is Kp = (PH2 * PI2) / (PHI)^2. Question: The decomposition of hydrogen iodide, 2HI (g) ----> 2H2 (g) + I2 (g), has rate constants of 9. Since there is an equal number of each element in the reactants and products of H2 + I2 = 2HI, the equation is balanced.95×10-2 at 731 K.3.200 atm, a partial pressure of I2 of 0. Hydrogen iodide decomposes according to the equation shown below.215 M H2, and 0. a. At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇌ 1/2 H2 (g) + 1/2 I2 (g) The value of Keq for the equilibrium H2 (g) + I2 (g) 2HI (g) is 794 at 25 °C. Suggest Corrections. The equilibrium constant, Kp, for the reaction H2(g) + I2(g) ⇌ 2HI(g) at 25°C can be calculated using the standard Gibbs free energy change, ΔG°, of 2.8.3 HI(g) 25.6 g HI.0900 MM . An additional 0.52 x 10-7 L/mols.9. [3] There is no effect on the equilibrium. Find Ea. H2 (g) + I2 (g) → 2HI (g) A student makes the following statements: Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H2 and product HI. What is the value of KcKc at this temperature? Express the equilibrium constant to three significant digits.95M[I2]=2. HI (g) is introduced into five identical 400-cm3 glass bulbs, and the five bulbs are maintained at 623 K.314 J/mol*K) (ln 1. At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇋1/2 H2 (g) + 1/2 I2 (g) 2. The value of Keq for the equilibrium H2 (g) + I2 (g) 2 HI (g) is 794 at 25 °C. Consider the following reaction: 2HI (g) H2 (g) + I2 (g) If 3. At the start of the reaction there are 0.7. Step 2.67 (d) CaCO3 (𝑠) CaO (𝑠)+CO2 At 25°C, the equilibrium constant, Kp, for the reaction H2(g) + I2(g) ⇌ 2HI(g) is approximately 0.45 M HI and no product.0552 mol of HI in a volume of 735 cm3 . 21. Consider the second-order reaction: 2HI (g)→H2 (g)+I2 (g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. What is the reaction quotient, Q, for this system when [H2] = 0.138 M d.100 mol I2 were placed in a 1.22. a) H2 ( g )+I2 ( g )⇌2HI ( g) Calculate Δ G ∘. The equilibrium constant for a system will be symbolized by the letter: K.50 at 400∘C (b) H2( g)+I2( g) ⇌ 2HI(g) Kc = 50. At a certain temperature, the equilibrium constant, Kc for this reaction is 53. Reaction Information Word Equation Hydrogen Iodide = Dihydrogen + Diiodine Consider the gas-phase reaction H2 (g) + I2 (g) ⇄ 2 HI (g) Suppose that a sealed flask containing H2 and I2 has been heated to 425 °C and the initial concentrations of H2 and I2 were each 0.